What is the inverse of f(x)=6x+7x^2 ?

The inverse of f(x)=6x+7x^2 is (-3+sqrt(7x+9))/7 ,-(sqrt(7x+9)+3)/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=6x+7x^2

inverse

f (x) = 6 x + 7 x^{2}

\frac{- 3 + 7 x + 9}{7}, - \frac{7 x + 9 + 3}{7}

Solution steps

y = 6 x + 7 x^{2}

Replace

x

with

y

x = 6 y + 7 y^{2}

Solve for

y, x = 6 y + 7 y^{2}

\frac{- 3 + 7 x + 9}{7}, - \frac{7 x + 9 + 3}{7}

\frac{5 x ^{3} - 8}{4}

f (x) = 4 - 3 cos (3 x - \frac{x}{3})

f (x) = \frac{( 3 + 2 x )}{( x - 7 )}

f (x) = e^{\frac{x + 1}{x - 1}}

\frac{10 x + 5}{2 x - 10}

What is the inverse of f(x)=6x+7x^2 ?
The inverse of f(x)=6x+7x^2 is (-3+sqrt(7x+9))/7 ,-(sqrt(7x+9)+3)/7