What is the inverse of 2\sqrt[3]{x+7}-10 ?

The inverse of 2\sqrt[3]{x+7}-10 is (75x)/2+(x^3)/8+(15x^2)/4+118

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inverse of 2\sqrt[3]{x+7}-10

inverse

\frac{75 x}{2} + \frac{x ^{3}}{8} + \frac{15 x ^{2}}{4} + 118

Solution steps

Replace

x

with

y

Solve for

\frac{75 x}{2} + \frac{x ^{3}}{8} + \frac{15 x ^{2}}{4} + 118

f (x) = \frac{8 x}{5 x - 1}

1000 e^{0.025 x}

f (x) = \frac{( x + 3 )}{x - 7}

f (x) = (\frac{3}{x + 2})

\frac{4}{( s - 1 ) ^{3}}

What is the inverse of 2\sqrt[3]{x+7}-10 ?
The inverse of 2\sqrt[3]{x+7}-10 is (75x)/2+(x^3)/8+(15x^2)/4+118