What is the inverse of f(x)=1+(4x)/(x+3) ?

The inverse of f(x)=1+(4x)/(x+3) is (-3x+3)/(x-5)

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inverse of f(x)=1+(4x)/(x+3)

inverse

f (x) = 1 + \frac{4 x}{x + 3}

\frac{- 3 x + 3}{x - 5}

Solution steps

y = 1 + \frac{4 x}{x + 3}

Replace

x

with

y

x = 1 + \frac{4 y}{y + 3}

Solve for

y, x = 1 + \frac{4 y}{y + 3}

\frac{- 3 x + 3}{x - 5}

- 0.25 x^{2} + 15 x - 200

2 x^{2} - \frac{1}{3} x - \frac{19}{14}

\frac{s + 2}{s ^{2} + 25}

f (x) = - \frac{1}{32} x^{2} - \frac{1}{8} x + \frac{3}{8}

f (x) = 30 x^{6}

What is the inverse of f(x)=1+(4x)/(x+3) ?
The inverse of f(x)=1+(4x)/(x+3) is (-3x+3)/(x-5)