What is the inverse of f(x)=3x^2+x ?

The inverse of f(x)=3x^2+x is (-1+sqrt(1+12x))/6 ,(-1-sqrt(1+12x))/6

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inverse of f(x)=3x^2+x

inverse

f (x) = 3 x^{2} + x

\frac{- 1 + 1 + 12 x}{6}, \frac{- 1 - 1 + 12 x}{6}

Solution steps

y = 3 x^{2} + x

Replace

x

with

y

x = 3 y^{2} + y

Solve for

y, x = 3 y^{2} + y

\frac{- 1 + 1 + 12 x}{6}, \frac{- 1 - 1 + 12 x}{6}

lo g_{10} (0.016576)

f (x) = 24 + 9 x

f (x) = (x - 9)^{2}, (9, \infty)

f (x) = (\frac{7}{40})

8^{7^{x}}

What is the inverse of f(x)=3x^2+x ?
The inverse of f(x)=3x^2+x is (-1+sqrt(1+12x))/6 ,(-1-sqrt(1+12x))/6