What is the inverse of f(x)=(x-9)^2,(9,infinity) ?

The inverse of f(x)=(x-9)^2,(9,infinity) is sqrt(x)+9,-sqrt(x)+9

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inverse of f(x)=(x-9)^2,(9,infinity)

inverse

f (x) = (x - 9)^{2}, (9, \infty)

x + 9, - x + 9

Solution steps

y = (x - 9)^{2}

Replace

x

with

y

x = (y - 9)^{2}

Solve for

y, x = (y - 9)^{2}

x + 9, - x + 9

f (x) = (\frac{7}{40})

8^{7^{x}}

\frac{x + 3}{2 x - 5}

h (x) = (- 15 x - 13)^{2}

f (x) = (x^{3} + 1)^{4}

What is the inverse of f(x)=(x-9)^2,(9,infinity) ?
The inverse of f(x)=(x-9)^2,(9,infinity) is sqrt(x)+9,-sqrt(x)+9