What is the inverse of f(x)=1x^2+2x+3 ?

The inverse of f(x)=1x^2+2x+3 is -1+sqrt(x-2),-sqrt(x-2)-1

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inverse of f(x)=1x^2+2x+3

inverse

f (x) = 1 x^{2} + 2 x + 3

- 1 + x - 2, - x - 2 - 1

Solution steps

y = 1 \cdot x^{2} + 2 x + 3

Replace

x

with

y

x = 1 \cdot y^{2} + 2 y + 3

Solve for

y, x = 1 y^{2} + 2 y + 3

- 1 + x - 2, - x - 2 - 1

f (x) = \frac{3 x + 2}{x - 3}

\frac{3 x - 2}{4}

f (x) = f (x) (x)^{- 1} (7) = - 5 x + 2

f (x) = ln (1) + 10 x

f (x) = \frac{3}{7 x + 4}

What is the inverse of f(x)=1x^2+2x+3 ?
The inverse of f(x)=1x^2+2x+3 is -1+sqrt(x-2),-sqrt(x-2)-1