What is the inverse of f(x)=f(x)(x)^{-1}(7)=-5x+2 ?

The inverse of f(x)=f(x)(x)^{-1}(7)=-5x+2 is -(x-2)/5

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inverse of f(x)=f(x)(x)^{-1}(7)=-5x+2

inverse

f (x) = f (x) (x)^{- 1} (7) = - 5 x + 2

- \frac{x - 2}{5}

Solution steps

y = - 5 x + 2

Replace

x

with

y

x = - 5 y + 2

Solve for

y, x = - 5 y + 2

- \frac{x - 2}{5}

f (x) = ln (1) + 10 x

f (x) = \frac{3}{7 x + 4}

f (x) = \frac{1}{3 x - 6}

\frac{π}{s ^{2} + 10 π s + 24 π ^{2}}

f (x) = \frac{- x - 4}{4 x + 3}

What is the inverse of f(x)=f(x)(x)^{-1}(7)=-5x+2 ?
The inverse of f(x)=f(x)(x)^{-1}(7)=-5x+2 is -(x-2)/5