What is the inverse of f(x)=2x^2+8x+1 ?

The inverse of f(x)=2x^2+8x+1 is (-8+sqrt(8x+56))/4 ,(-8-sqrt(8x+56))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2+8x+1

inverse

f (x) = 2 x^{2} + 8 x + 1

\frac{- 8 + 8 x + 56}{4}, \frac{- 8 - 8 x + 56}{4}

Solution steps

y = 2 x^{2} + 8 x + 1

Replace

x

with

y

x = 2 y^{2} + 8 y + 1

Solve for

y, x = 2 y^{2} + 8 y + 1

\frac{- 8 + 8 x + 56}{4}, \frac{- 8 - 8 x + 56}{4}

\frac{123}{51 - X}

f (x) = 4 x^{4} - 12 x^{2} + 9

f (x) = - \frac{x ^{2}}{2} + x + \frac{1}{2}

f (x) = \frac{t ^{2} + 4 t - 12}{t ^{2} - 9 t + 14}

f (x) = \frac{1}{2} \cdot 1 0^{3 x}

What is the inverse of f(x)=2x^2+8x+1 ?
The inverse of f(x)=2x^2+8x+1 is (-8+sqrt(8x+56))/4 ,(-8-sqrt(8x+56))/4