What is the inverse of (x^2)/(-x^2+4) ?

The inverse of (x^2)/(-x^2+4) is (2sqrt(x)sqrt(x+1))/(x+1),-(2sqrt(x)sqrt(x+1))/(x+1)

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inverse of (x^2)/(-x^2+4)

inverse

\frac{x ^{2}}{- x ^{2} + 4}

\frac{2 x x + 1}{x + 1}, - \frac{2 x x + 1}{x + 1}

Solution steps

y = \frac{x ^{2}}{- x ^{2} + 4}

Replace

x

with

y

x = \frac{y ^{2}}{- y ^{2} + 4}

Solve for

y, x = \frac{y ^{2}}{- y ^{2} + 4}

\frac{2 x x + 1}{x + 1}, - \frac{2 x x + 1}{x + 1}

f (x) = 1 + lo g_{\frac{1}{e}} (2 - x)

f (x) = x 3 + 3 x 2 + 1

f (x) = \frac{( 7 x + 3 )}{( x - 5 )}

f (x) = d + 1

\frac{- 3 x + 4}{7 x + 9}

What is the inverse of (x^2)/(-x^2+4) ?
The inverse of (x^2)/(-x^2+4) is (2sqrt(x)sqrt(x+1))/(x+1),-(2sqrt(x)sqrt(x+1))/(x+1)