What is the inverse of f(x)=(2x-5)^2 ?

The inverse of f(x)=(2x-5)^2 is (sqrt(x)+5)/2 ,(-sqrt(x)+5)/2

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inverse of f(x)=(2x-5)^2

inverse

f (x) = (2 x - 5)^{2}

\frac{x + 5}{2}, \frac{- x + 5}{2}

Solution steps

y = (2 x - 5)^{2}

Replace

x

with

y

x = (2 y - 5)^{2}

Solve for

y, x = (2 y - 5)^{2}

\frac{x + 5}{2}, \frac{- x + 5}{2}

\frac{3}{x - 8}

g (x) = \frac{9 x}{7 x - 9}

x = 2^{y}

f (x) = 1 - \frac{1}{2} e^{- 2 b x}

2 x + 3 y x + 2 y = 2

What is the inverse of f(x)=(2x-5)^2 ?
The inverse of f(x)=(2x-5)^2 is (sqrt(x)+5)/2 ,(-sqrt(x)+5)/2