What is the inverse of (1+2*z^{-2})/(1+1/(2*z^{-2))} ?

The inverse of (1+2*z^{-2})/(1+1/(2*z^{-2))} is sqrt(2/z),-sqrt(2/z)

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inverse of (1+2z^{-2})/(1+1/(2z^{-2))}

inverse

\frac{1 + 2 \cdot z ^{- 2}}{1 + \frac{1}{2 \cdot z ^{- 2}}}

\frac{2}{z}, - \frac{2}{z}

Solution steps

y = \frac{1 + 2 z ^{- 2}}{1 + \frac{1}{2 z ^{- 2}}}

Replace

z

with

y

z = \frac{1 + 2 y ^{- 2}}{1 + \frac{1}{2 y ^{- 2}}}

Solve for

y, z = \frac{1 + 2 \cdot y ^{- 2}}{1 + \frac{1}{2 \cdot y ^{- 2}}}

\frac{2}{z}, - \frac{2}{z}

\frac{x - 4}{2 x + 1}

f (x) = - 0.7 x + 35

f (x) = 3 2 x - 2

f (x) = 8 + 3 x - 9

\frac{3}{8 x ^{\frac{5}{2}}}

What is the inverse of (1+2*z^{-2})/(1+1/(2*z^{-2))} ?
The inverse of (1+2*z^{-2})/(1+1/(2*z^{-2))} is sqrt(2/z),-sqrt(2/z)