What is the inverse of f(x)=\sqrt[3]{2x-2} ?

The inverse of f(x)=\sqrt[3]{2x-2} is (x^3+2)/2

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inverse of f(x)=\sqrt[3]{2x-2}

inverse

f (x) = 3 2 x - 2

\frac{x ^{3} + 2}{2}

Solution steps

y = 3 2 x - 2

Replace

x

with

y

x = 3 2 y - 2

Solve for

y, x = 3 2 y - 2

\frac{x ^{3} + 2}{2}

f (x) = 8 + 3 x - 9

\frac{3}{8 x ^{\frac{5}{2}}}

x^{2} + 9 x - 20

f (x) = \frac{2}{e - π} (x - π) - 1

\frac{s}{s ^{2} - 6 s - 7}

What is the inverse of f(x)=\sqrt[3]{2x-2} ?
The inverse of f(x)=\sqrt[3]{2x-2} is (x^3+2)/2