What is the inverse of f(x)=(x^2+6)^{-1} ?

The inverse of f(x)=(x^2+6)^{-1} is sqrt((1-6x)/x),-sqrt((1-6x)/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x^2+6)^{-1}

inverse

f (x) = (x^{2} + 6)^{- 1}

\frac{1 - 6 x}{x}, - \frac{1 - 6 x}{x}

Solution steps

y = (x^{2} + 6)^{- 1}

Replace

x

with

y

x = (y^{2} + 6)^{- 1}

Solve for

y, x = (y^{2} + 6)^{- 1}

\frac{1 - 6 x}{x}, - \frac{1 - 6 x}{x}

3^{n}

f (x) = \frac{( 10 - x )}{2}

\frac{8 s + 6}{s ( 2 s + 7 )}

f (x) = \frac{x ^{2} + 2}{4}

f (x) = \frac{2 x - 1}{3 x + 6}

What is the inverse of f(x)=(x^2+6)^{-1} ?
The inverse of f(x)=(x^2+6)^{-1} is sqrt((1-6x)/x),-sqrt((1-6x)/x)