What is the inverse of (8s+6)/(s(2s+7)) ?

The inverse of (8s+6)/(s(2s+7)) is (-7s+8+sqrt(49s^2-64s+64))/(4s),(-7s+8-sqrt(49s^2-64s+64))/(4s)

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inverse of (8s+6)/(s(2s+7))

inverse

\frac{8 s + 6}{s ( 2 s + 7 )}

\frac{- 7 s + 8 + 49 s ^{2} - 64 s + 64}{4 s}, \frac{- 7 s + 8 - 49 s ^{2} - 64 s + 64}{4 s}

Solution steps

y = \frac{8 s + 6}{s ( 2 s + 7 )}

Replace

s

with

y

s = \frac{8 y + 6}{y ( 2 y + 7 )}

Solve for

y, s = \frac{8 y + 6}{y ( 2 y + 7 )}

\frac{- 7 s + 8 + 49 s ^{2} - 64 s + 64}{4 s}, \frac{- 7 s + 8 - 49 s ^{2} - 64 s + 64}{4 s}

f (x) = \frac{x ^{2} + 2}{4}

f (x) = \frac{2 x - 1}{3 x + 6}

f (x) = \frac{1}{3 x - 14}

y = lo g_{2} (x - 1) + 1

F (x) = \frac{1}{7} x - 7

What is the inverse of (8s+6)/(s(2s+7)) ?
The inverse of (8s+6)/(s(2s+7)) is (-7s+8+sqrt(49s^2-64s+64))/(4s),(-7s+8-sqrt(49s^2-64s+64))/(4s)