en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=log_{2}(x-1)+1

Solution

inverse

y = lo g_{2} (x - 1) + 1

Solution

2^{x - 1} + 1

Solution steps

y = lo g_{2} (x - 1) + 1

Replace

x

with

y

x = lo g_{2} (y - 1) + 1

Solve for

y, x = lo g_{2} (y - 1) + 1

2^{x - 1} + 1

Popular Examples

inverse of F(x)= 1/7 x-7 inverse

F (x) = \frac{1}{7} x - 7

inverse of f(x)=(4)^{(7)^{(x)}}inverse

f (x) = (4)^{(7)^{(x)}}

inverse of-e^{x-9}-2 inverse

- e^{x - 9} - 2

inverse of f(x)=9e^{8x}+7 inverse

f (x) = 9 e^{8 x} + 7

inverse of f(x)=sqrt((x+8pi)/(2pi))-2 inverse

f (x) = \frac{x + 8 π}{2 π} - 2

Frequently Asked Questions (FAQ)

What is the inverse of y=log_{2}(x-1)+1 ?
The inverse of y=log_{2}(x-1)+1 is 2^{x-1}+1