What is the inverse of f(x)=2x^2+x-1 ?

The inverse of f(x)=2x^2+x-1 is (-1+sqrt(8x+9))/4 ,(-1-sqrt(8x+9))/4

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inverse of f(x)=2x^2+x-1

inverse

f (x) = 2 x^{2} + x - 1

\frac{- 1 + 8 x + 9}{4}, \frac{- 1 - 8 x + 9}{4}

Solution steps

y = 2 x^{2} + x - 1

Replace

x

with

y

x = 2 y^{2} + y - 1

Solve for

y, x = 2 y^{2} + y - 1

\frac{- 1 + 8 x + 9}{4}, \frac{- 1 - 8 x + 9}{4}

f (x) = \frac{e ^{x} + 4}{2}

\frac{1 + 7 x}{7 - 5 x}

x^{2} = 2 y

\frac{( 2 x + 3 )}{( 7 x - 8 )}

g (x) = \frac{4}{x - 2} + 3

What is the inverse of f(x)=2x^2+x-1 ?
The inverse of f(x)=2x^2+x-1 is (-1+sqrt(8x+9))/4 ,(-1-sqrt(8x+9))/4