What is the inverse of ((2x+3))/((7x-8)) ?

The inverse of ((2x+3))/((7x-8)) is (3+8x)/(7x-2)

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inverse of ((2x+3))/((7x-8))

inverse

\frac{( 2 x + 3 )}{( 7 x - 8 )}

\frac{3 + 8 x}{7 x - 2}

Solution steps

y = \frac{2 x + 3}{7 x - 8}

Replace

x

with

y

x = \frac{2 y + 3}{7 y - 8}

Solve for

y, x = \frac{2 y + 3}{7 y - 8}

\frac{3 + 8 x}{7 x - 2}

g (x) = \frac{4}{x - 2} + 3

f (x) = (x + 8)^{2} - 3

f (x) = - \frac{x}{4} + \frac{3}{2}

y = \frac{5 + x}{4 - 2 x}

f (y) = \frac{1}{3} (2^{3 x + 1}) - 1

What is the inverse of ((2x+3))/((7x-8)) ?
The inverse of ((2x+3))/((7x-8)) is (3+8x)/(7x-2)