What is the inverse of y^{-1}=e^{(x+4)/3}-2 ?

The inverse of y^{-1}=e^{(x+4)/3}-2 is 3ln(x+2)-4

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inverse of y^{-1}=e^{(x+4)/3}-2

inverse

y^{- 1} = e^{\frac{x + 4}{3}} - 2

3 ln (x + 2) - 4

Solution steps

y = e^{\frac{x + 4}{3}} - 2

Replace

x

with

y

x = e^{\frac{y + 4}{3}} - 2

Solve for

y, x = e^{\frac{y + 4}{3}} - 2

3 ln (x + 2) - 4

f (x) = \frac{( x ^{2} )}{( x + 1 )}

\frac{x - 4}{x ^{2} + 8 x + 16}

f (x) = \frac{7}{4 x + 5}

q (x) = - 2 (- 3 x + 2)

f (x) = 2 e^{3 x^{2}}

What is the inverse of y^{-1}=e^{(x+4)/3}-2 ?
The inverse of y^{-1}=e^{(x+4)/3}-2 is 3ln(x+2)-4