What is the inverse of+16+\sqrt[3]{x} ?

The inverse of+16+\sqrt[3]{x} is x^3-48x^2+768x-4096

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inverse of+16+\sqrt[3]{x}

inverse

x^{3} - 48 x^{2} + 768 x - 4096

Solution steps

Replace

x

with

y

Solve for

x^{3} - 48 x^{2} + 768 x - 4096

f (x) = 2 + 4 - x^{2}

f (x) = \frac{2}{3 x + 4}

f (x) = \frac{2 x - 6}{5 x - 1}

\frac{x ^{2} - x + 1}{x ^{2} + 1}

\frac{8 x}{3}

What is the inverse of+16+\sqrt[3]{x} ?
The inverse of+16+\sqrt[3]{x} is x^3-48x^2+768x-4096