What is the inverse of (dy)/y g(x)=arccos(x) ?

The inverse of (dy)/y g(x)=arccos(x) is cos(x)

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inverse of (dy)/y g(x)=arccos(x)

inverse

\frac{d y}{y} g (x) = arccos (x)

cos (x)

Solution steps

arccos (a) = b \Rightarrow a = cos (b)

cos (y)

Substitute

y = x

cos (x)

f (x) = 5 - \frac{x}{3 x + 1}

y = \frac{5 - 2 x}{4 x - 2}

\frac{1}{( x - 2 ) ^{2}} + 1

2 (x + 7) - 3

f (x) = \frac{2}{2 - x}

What is the inverse of (dy)/y g(x)=arccos(x) ?
The inverse of (dy)/y g(x)=arccos(x) is cos(x)