What is the inverse of f(x)=(x-4)^2-8 ?

The inverse of f(x)=(x-4)^2-8 is sqrt(x+8)+4,-sqrt(x+8)+4

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inverse of f(x)=(x-4)^2-8

inverse

f (x) = (x - 4)^{2} - 8

x + 8 + 4, - x + 8 + 4

Solution steps

y = (x - 4)^{2} - 8

Replace

x

with

y

x = (y - 4)^{2} - 8

Solve for

y, x = (y - 4)^{2} - 8

x + 8 + 4, - x + 8 + 4

f (x) = \frac{7 x - 9}{6 x + 5}

\frac{lo g _{5} ( 3 ^{(x)} + 9 )}{( 2 )}

\frac{( - lo g _{2} ( x ) + 5 )}{8}

f (x) = 5 - lo g_{2} (x + 1)

y = - 3 cos (4 x)

What is the inverse of f(x)=(x-4)^2-8 ?
The inverse of f(x)=(x-4)^2-8 is sqrt(x+8)+4,-sqrt(x+8)+4