What is the inverse of f(x)=((7x-2))/(x+9) ?

The inverse of f(x)=((7x-2))/(x+9) is (-2-9x)/(x-7)

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inverse of f(x)=((7x-2))/(x+9)

inverse

f (x) = \frac{( 7 x - 2 )}{x + 9}

\frac{- 2 - 9 x}{x - 7}

Solution steps

y = \frac{7 x - 2}{x + 9}

Replace

x

with

y

x = \frac{7 y - 2}{y + 9}

Solve for

y, x = \frac{7 y - 2}{y + 9}

\frac{- 2 - 9 x}{x - 7}

\frac{1}{( s + 2 ) ( s + 5 )}

f (x) = \frac{5 x + 4}{8 x - 7}

ln (11 x^{2} + 3)

\frac{( \frac{8}{5} )}{( \frac{9}{4} )}

f (x) = \frac{1}{8 x} - 3

What is the inverse of f(x)=((7x-2))/(x+9) ?
The inverse of f(x)=((7x-2))/(x+9) is (-2-9x)/(x-7)