What is the inverse of f(x)=-1/((25))x^2 ?

The inverse of f(x)=-1/((25))x^2 is 5sqrt(-x),-5sqrt(-x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-1/((25))x^2

inverse

f (x) = - \frac{1}{( 25 )} x^{2}

5 - x, - 5 - x

Solution steps

y = - \frac{1}{25} x^{2}

Replace

x

with

y

x = - \frac{1}{25} y^{2}

Solve for

y, x = - \frac{1}{25} y^{2}

5 - x, - 5 - x

f (x) = - \frac{2}{3} x + 9

\frac{- 5 x + 3}{8 + x}

f (x) = lo g_{10} (\frac{x}{( x + 1 )})

- 2 (x + 1)^{2} + 4

f (x) = - \frac{2}{3} x + 8

What is the inverse of f(x)=-1/((25))x^2 ?
The inverse of f(x)=-1/((25))x^2 is 5sqrt(-x),-5sqrt(-x)