What is the inverse of-2(x+1)^2+4 ?

The inverse of-2(x+1)^2+4 is sqrt(-(x-4)/2)-1,-sqrt(-(x-4)/2)-1

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inverse of-2(x+1)^2+4

inverse

- 2 (x + 1)^{2} + 4

- \frac{x - 4}{2} - 1, - - \frac{x - 4}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} + 4

Replace

x

with

y

x = - 2 (y + 1)^{2} + 4

Solve for

y, x = - 2 (y + 1)^{2} + 4

- \frac{x - 4}{2} - 1, - - \frac{x - 4}{2} - 1

f (x) = - \frac{2}{3} x + 8

f (x) = \frac{x - 1}{x - 4}

\frac{3}{4 + x}

y = \frac{7 x - 9}{9 x + 4}

\frac{( x + 9 )}{x - 3}

What is the inverse of-2(x+1)^2+4 ?
The inverse of-2(x+1)^2+4 is sqrt(-(x-4)/2)-1,-sqrt(-(x-4)/2)-1