What is the inverse of f(x)=(x^2)/(x+2) ?

The inverse of f(x)=(x^2)/(x+2) is (x+sqrt(x^2+8x))/2 ,(x-sqrt(x^2+8x))/2

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inverse of f(x)=(x^2)/(x+2)

inverse

f (x) = \frac{x ^{2}}{x + 2}

\frac{x + x ^{2} + 8 x}{2}, \frac{x - x ^{2} + 8 x}{2}

Solution steps

y = \frac{x ^{2}}{x + 2}

Replace

x

with

y

x = \frac{y ^{2}}{y + 2}

Solve for

y, x = \frac{y ^{2}}{y + 2}

\frac{x + x ^{2} + 8 x}{2}, \frac{x - x ^{2} + 8 x}{2}

f (x) = 4^{0.02 x}

y = \frac{5}{5 x}

x^{2} + 8 x - 9

f (x) = \frac{10 x + 5}{- 9 x - 3}

f (x) = \frac{- 5}{3 x + 2}

What is the inverse of f(x)=(x^2)/(x+2) ?
The inverse of f(x)=(x^2)/(x+2) is (x+sqrt(x^2+8x))/2 ,(x-sqrt(x^2+8x))/2