What is the inverse of f(x)=log_{10}(x+1)-1 ?

The inverse of f(x)=log_{10}(x+1)-1 is 10^{x+1}-1

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inverse of f(x)=log_{10}(x+1)-1

inverse

f (x) = lo g_{10} (x + 1) - 1

1 0^{x + 1} - 1

Solution steps

y = lo g_{10} (x + 1) - 1

Replace

x

with

y

x = lo g_{10} (y + 1) - 1

Solve for

y, x = lo g_{10} (y + 1) - 1

1 0^{x + 1} - 1

f (x) = 3 \cdot 2^{x - 1} + 1

f (x) = lo g_{10} (x + 1) - 4

y = - 2^{x}

2 \frac{3 x ^{2}}{x}

\frac{20}{1 + e ^{- 0.3 \cdot (t - 15)}}

What is the inverse of f(x)=log_{10}(x+1)-1 ?
The inverse of f(x)=log_{10}(x+1)-1 is 10^{x+1}-1