What is the inverse of f(x)=0.005x^3 ?

The inverse of f(x)=0.005x^3 is 2\sqrt[3]{25}\sqrt[3]{x}

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inverse of f(x)=0.005x^3

inverse

f (x) = 0.005 x^{3}

2325 3 x

Solution steps

y = 0.005 x^{3}

Replace

x

with

y

x = 0.005 y^{3}

Solve for

y, x = 0.005 y^{3}

2325 3 x

f (x) = arctan (\frac{1}{3})

f (x) = \frac{1}{2} x^{2} - 4 x + \frac{39}{8}

\frac{x ^{2} + x - 30}{x - 6}

f (x) = - (x + 1) 2 - 1, x < - \frac{π}{2}

\frac{6 x}{x - 4}

What is the inverse of f(x)=0.005x^3 ?
The inverse of f(x)=0.005x^3 is 2\sqrt[3]{25}\sqrt[3]{x}