What is the inverse of-(sqrt(5-2x))/(7x) ?

The inverse of-(sqrt(5-2x))/(7x) is (-1+sqrt(245x^2+1))/(49x^2),-(sqrt(245x^2+1)+1)/(49x^2)

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inverse of-(sqrt(5-2x))/(7x)

inverse

- \frac{5 - 2 x}{7 x}

\frac{- 1 + 245 x ^{2} + 1}{49 x ^{2}}, - \frac{245 x ^{2} + 1 + 1}{49 x ^{2}}

Solution steps

y = - \frac{5 - 2 x}{7 x}

Replace

x

with

y

x = - \frac{5 - 2 y}{7 y}

Solve for

y, x = - \frac{5 - 2 y}{7 y}

\frac{- 1 + 245 x ^{2} + 1}{49 x ^{2}}, - \frac{245 x ^{2} + 1 + 1}{49 x ^{2}}

\frac{15 x ^{2} - 2}{3 x ^{2}}

f (x) = \frac{- 4 x + 3}{x - 6}

\frac{9 x - 8}{x + 4}

f (x) = x^{2} - 4 x + 4, x \leq 0

6 x + 12

What is the inverse of-(sqrt(5-2x))/(7x) ?
The inverse of-(sqrt(5-2x))/(7x) is (-1+sqrt(245x^2+1))/(49x^2),-(sqrt(245x^2+1)+1)/(49x^2)