What is the inverse of f(x)=-6(x-3)^2-2 ?

The inverse of f(x)=-6(x-3)^2-2 is sqrt(-(x+2)/6)+3,-sqrt(-(x+2)/6)+3

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inverse of f(x)=-6(x-3)^2-2

inverse

f (x) = - 6 (x - 3)^{2} - 2

- \frac{x + 2}{6} + 3, - - \frac{x + 2}{6} + 3

Solution steps

y = - 6 (x - 3)^{2} - 2

Replace

x

with

y

x = - 6 (y - 3)^{2} - 2

Solve for

y, x = - 6 (y - 3)^{2} - 2

- \frac{x + 2}{6} + 3, - - \frac{x + 2}{6} + 3

f (x) = \frac{3 x - 2}{x - 5}

f (x) = 4 \cdot lo g_{\frac{1}{2}} (- x + 10)

f (x) = \frac{x ^{2} - 1}{x ^{2} - 9}

f (x) = Y (x) (x)^{1} = \frac{x - 4}{2} + 3

(x - 7)^{3} + 8

What is the inverse of f(x)=-6(x-3)^2-2 ?
The inverse of f(x)=-6(x-3)^2-2 is sqrt(-(x+2)/6)+3,-sqrt(-(x+2)/6)+3