What is the inverse of (x^2)/(1-x^2) ?

The inverse of (x^2)/(1-x^2) is sqrt(x/(x+1)),-sqrt(x/(x+1))

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inverse of (x^2)/(1-x^2)

inverse

\frac{x ^{2}}{1 - x ^{2}}

\frac{x}{x + 1}, - \frac{x}{x + 1}

Solution steps

y = \frac{x ^{2}}{1 - x ^{2}}

Replace

x

with

y

x = \frac{y ^{2}}{1 - y ^{2}}

Solve for

y, x = \frac{y ^{2}}{1 - y ^{2}}

\frac{x}{x + 1}, - \frac{x}{x + 1}

\frac{2}{s + 1}

f (x) = 3 - \frac{1}{x - 4}

f (x) = \frac{x + 2 π}{8 π} - 2

\frac{2}{s + 2}

tan (0.68)

What is the inverse of (x^2)/(1-x^2) ?
The inverse of (x^2)/(1-x^2) is sqrt(x/(x+1)),-sqrt(x/(x+1))