What is the inverse of f(x)=sqrt((x+2pi)/(8pi))-2 ?

The inverse of f(x)=sqrt((x+2pi)/(8pi))-2 is 8pix^2+32pix+30pi

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inverse of f(x)=sqrt((x+2pi)/(8pi))-2

inverse

f (x) = \frac{x + 2 π}{8 π} - 2

8 π x^{2} + 32 π x + 30 π

Solution steps

y = \frac{x + 2 π}{8 π} - 2

Replace

x

with

y

x = \frac{y + 2 π}{8 π} - 2

Solve for

y, x = \frac{y + 2 π}{8 π} - 2

8 π x^{2} + 32 π x + 30 π

\frac{2}{s + 2}

tan (0.68)

arccos (- x)

f (x) = (\frac{( 1 - 3 x )}{( 2 x + 1 )})

f (x) = 4 + 2 x - 3

What is the inverse of f(x)=sqrt((x+2pi)/(8pi))-2 ?
The inverse of f(x)=sqrt((x+2pi)/(8pi))-2 is 8pix^2+32pix+30pi