What is the inverse of f(x)=(((1-3x))/((2x+1))) ?

The inverse of f(x)=(((1-3x))/((2x+1))) is (1-x)/(2x+3)

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inverse of f(x)=(((1-3x))/((2x+1)))

inverse

f (x) = (\frac{( 1 - 3 x )}{( 2 x + 1 )})

\frac{1 - x}{2 x + 3}

Solution steps

y = \frac{1 - 3 x}{2 x + 1}

Replace

x

with

y

x = \frac{1 - 3 y}{2 y + 1}

Solve for

y, x = \frac{1 - 3 y}{2 y + 1}

\frac{1 - x}{2 x + 3}

f (x) = 4 + 2 x - 3

y = \frac{5 x ^{2}}{2}

f (x) = ln (x^{2} - 2)

\frac{3}{2} x^{2} + \frac{9}{2} x

f (y) = 3 x^{2} + x

What is the inverse of f(x)=(((1-3x))/((2x+1))) ?
The inverse of f(x)=(((1-3x))/((2x+1))) is (1-x)/(2x+3)