What is the inverse of f(y)=3x^2+x ?

The inverse of f(y)=3x^2+x is (-1+sqrt(1+12x))/6 ,(-1-sqrt(1+12x))/6

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inverse of f(y)=3x^2+x

inverse

f (y) = 3 x^{2} + x

\frac{- 1 + 1 + 12 x}{6}, \frac{- 1 - 1 + 12 x}{6}

Solution steps

y = 3 x^{2} + x

Replace

x

with

y

x = 3 y^{2} + y

Solve for

y, x = 3 y^{2} + y

\frac{- 1 + 1 + 12 x}{6}, \frac{- 1 - 1 + 12 x}{6}

f (x) = (\frac{4}{( x - 4 ) ^{2}})

f (x) = ln (x + 1) - 4

f (x) = \frac{5 x - 11}{10}

\frac{- 2 s - 8}{s ^{2} + 4 s + 4}

g (x) = \frac{( 7 x + 18 )}{2}

What is the inverse of f(y)=3x^2+x ?
The inverse of f(y)=3x^2+x is (-1+sqrt(1+12x))/6 ,(-1-sqrt(1+12x))/6