What is the inverse of d/d (x^2+2x+4) ?

The inverse of d/d (x^2+2x+4) is -1+sqrt(x-3),-sqrt(x-3)-1

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inverse of d/d (x^2+2x+4)

inverse

\frac{d}{d} (x^{2} + 2 x + 4)

- 1 + x - 3, - x - 3 - 1

Solution steps

y = \frac{d}{d} (x^{2} + 2 x + 4)

Replace

x

with

y

x = \frac{d}{d} (y^{2} + 2 y + 4)

Solve for

y, x = \frac{d}{d} (y^{2} + 2 y + 4)

- 1 + x - 3, - x - 3 - 1

Y^{2}

h (x) = x + 7 - 1

y = \frac{( 2 x + 1 )}{3 - 2 x}

f (x) = lo g_{e} (3 x)

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What is the inverse of d/d (x^2+2x+4) ?
The inverse of d/d (x^2+2x+4) is -1+sqrt(x-3),-sqrt(x-3)-1