What is the inverse of y=((x^2))/8 ,(x>0) ?

The inverse of y=((x^2))/8 ,(x>0) is 2sqrt(2)sqrt(x),-2sqrt(2)sqrt(x)

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inverse of y=((x^2))/8 ,(x>0)

inverse

y = \frac{( x ^{2} )}{8}, (x > 0)

22 x, - 22 x

Solution steps

y = \frac{x ^{2}}{8}

Replace

x

with

y

x = \frac{y ^{2}}{8}

Solve for

y, x = \frac{y ^{2}}{8}

22 x, - 22 x

f (x) = \frac{( 2 x - 3 ) + 3}{2}

375 + 0.1 q

\frac{1}{s + 1} - \frac{1}{s + 2}

f (x) = \frac{3 ( x + 3 )}{2} + 4

y = \frac{4 x}{x + 1}

What is the inverse of y=((x^2))/8 ,(x>0) ?
The inverse of y=((x^2))/8 ,(x>0) is 2sqrt(2)sqrt(x),-2sqrt(2)sqrt(x)