What is the inverse of f(x)=3(x-1)^2-5 ?

The inverse of f(x)=3(x-1)^2-5 is sqrt((x+5)/3)+1,-sqrt((x+5)/3)+1

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inverse of f(x)=3(x-1)^2-5

inverse

f (x) = 3 (x - 1)^{2} - 5

\frac{x + 5}{3} + 1, - \frac{x + 5}{3} + 1

Solution steps

y = 3 (x - 1)^{2} - 5

Replace

x

with

y

x = 3 (y - 1)^{2} - 5

Solve for

y, x = 3 (y - 1)^{2} - 5

\frac{x + 5}{3} + 1, - \frac{x + 5}{3} + 1

f (x) = x^{2} - 4 x + 17

f (x) = 0.25 x

f (x) = \frac{2 x - 3}{x + 3}

9 y - 8

f (x) = 18 ln (tan (x))

What is the inverse of f(x)=3(x-1)^2-5 ?
The inverse of f(x)=3(x-1)^2-5 is sqrt((x+5)/3)+1,-sqrt((x+5)/3)+1