What is the inverse of f(x)=((x+1))/(sqrt(x)) ?

The inverse of f(x)=((x+1))/(sqrt(x)) is (-2+x^2+xsqrt(x^2-4))/2 ,(-2+x^2-xsqrt(x^2-4))/2

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inverse of f(x)=((x+1))/(sqrt(x))

inverse

f (x) = \frac{( x + 1 )}{x}

\frac{- 2 + x ^{2} + x x ^{2} - 4}{2}, \frac{- 2 + x ^{2} - x x ^{2} - 4}{2}

Solution steps

y = \frac{x + 1}{x}

Replace

x

with

y

x = \frac{y + 1}{y}

Solve for

y, x = \frac{y + 1}{y}

\frac{- 2 + x ^{2} + x x ^{2} - 4}{2}, \frac{- 2 + x ^{2} - x x ^{2} - 4}{2}

1 - e^{- \frac{x}{2}}

f (x) = \frac{2 x - 3}{4 x + 6}

f (x) = 3 x - 10 + 8

f (x) = 3 x - 10 + 4

ln (x) 4.77

What is the inverse of f(x)=((x+1))/(sqrt(x)) ?
The inverse of f(x)=((x+1))/(sqrt(x)) is (-2+x^2+xsqrt(x^2-4))/2 ,(-2+x^2-xsqrt(x^2-4))/2