What is the inverse of f(x)=x^4+4,x<= 0 ?

The inverse of f(x)=x^4+4,x<= 0 is \sqrt[4]{x-4},-\sqrt[4]{x-4}

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inverse of f(x)=x^4+4,x<= 0

inverse

f (x) = x^{4} + 4, x \leq 0

4 x - 4, - 4 x - 4

Solution steps

y = x^{4} + 4

Replace

x

with

y

x = y^{4} + 4

Solve for

y, x = y^{4} + 4

4 x - 4, - 4 x - 4

f (x) = x^{2} - 18 x + 81

f (x) = 9 \cdot 2^{2 x - 1} - 1

f (x) = 5 - \frac{1}{2} x

y = \frac{5 x - 3}{x}

f (x) = x^{2} + 4 x + 5, x \leq - 2

What is the inverse of f(x)=x^4+4,x<= 0 ?
The inverse of f(x)=x^4+4,x<= 0 is \sqrt[4]{x-4},-\sqrt[4]{x-4}