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Popular >

inverse of g(x)=(x+1)/(x-1)

Solution

inverse

g (x) = \frac{x + 1}{x - 1}

Solution

\frac{1 + x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 1}

Replace

x

with

y

x = \frac{y + 1}{y - 1}

Solve for

y, x = \frac{y + 1}{y - 1}

\frac{1 + x}{x - 1}

Graph

Popular Examples

inverse of f(x)= 1/2 x^2-8 inverse

f (x) = \frac{1}{2} x^{2} - 8

inverse of f(x)=-x^2+1,x>= 0 inverse

f (x) = - x^{2} + 1, x \geq 0

inverse of f(x)=-2(x+1)^3 inverse

f (x) = - 2 (x + 1)^{3}

inverse of (x^2-4)/(x-2)inverse

\frac{x ^{2} - 4}{x - 2}

inverse of y=2^{x-1}+5 inverse

y = 2^{x - 1} + 5

Frequently Asked Questions (FAQ)

What is the inverse of g(x)=(x+1)/(x-1) ?
The inverse of g(x)=(x+1)/(x-1) is (1+x)/(x-1)