What is the inverse of f(x)=f(x)= 9/5 c+32 ?

The inverse of f(x)=f(x)= 9/5 c+32 is (5c-160)/9

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inverse of f(x)=f(x)= 9/5 c+32

inverse

f (x) = f (x) = \frac{9}{5} c + 32

\frac{5 c - 160}{9}

Solution steps

y = \frac{9}{5} c + 32

Replace

c

with

y

c = \frac{9}{5} y + 32

Solve for

y, c = \frac{9}{5} y + 32

\frac{5 c - 160}{9}

f (x) = \frac{3 x - 8}{2 x + 1}

3 x - 3 x^{2}

f (x) = - \frac{x}{2 x + 2}

f (x) = - 3 x - 18

f (x) = 1 - e^{(- 0.03 \cdot x^{1.2})}

What is the inverse of f(x)=f(x)= 9/5 c+32 ?
The inverse of f(x)=f(x)= 9/5 c+32 is (5c-160)/9