What is the inverse of f(x)=(sqrt(3-x))/x ?

The inverse of f(x)=(sqrt(3-x))/x is (-1+sqrt(1+12x^2))/(2x^2),(-1-sqrt(1+12x^2))/(2x^2)

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inverse of f(x)=(sqrt(3-x))/x

inverse

f (x) = \frac{3 - x}{x}

\frac{- 1 + 1 + 12 x ^{2}}{2 x ^{2}}, \frac{- 1 - 1 + 12 x ^{2}}{2 x ^{2}}

Solution steps

y = \frac{3 - x}{x}

Replace

x

with

y

x = \frac{3 - y}{y}

Solve for

y, x = \frac{3 - y}{y}

\frac{- 1 + 1 + 12 x ^{2}}{2 x ^{2}}, \frac{- 1 - 1 + 12 x ^{2}}{2 x ^{2}}

f (x) = x^{(- \frac{3}{2})}

\frac{25}{10} \frac{15}{x}

f (x) = 3 x + 11 + 12

x = 0.4 t + 6.6

y = 2 x + 10

What is the inverse of f(x)=(sqrt(3-x))/x ?
The inverse of f(x)=(sqrt(3-x))/x is (-1+sqrt(1+12x^2))/(2x^2),(-1-sqrt(1+12x^2))/(2x^2)