What is the inverse of-4sqrt(x-1)+7 ?

The inverse of-4sqrt(x-1)+7 is (x^2+49}{16}-\frac{7x)/8+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of-4sqrt(x-1)+7

inverse

- 4 x - 1 + 7

\frac{x ^{2} + 49}{16} - \frac{7 x}{8} + 1

Solution steps

y = - 4 x - 1 + 7

Replace

x

with

y

x = - 4 y - 1 + 7

Solve for

y, x = - 4 y - 1 + 7

\frac{x ^{2} + 49}{16} - \frac{7 x}{8} + 1

\frac{2 x ^{3} - 1}{5}

\frac{7 + x}{8 - x}

f (x) = \frac{5 - 9 ( - 2 )}{( - 2 ) - 1}

f (x) = 7 (\frac{x - 1}{2})

f (x) = \frac{1}{x ^{2} + 3 x + 2}

What is the inverse of-4sqrt(x-1)+7 ?
The inverse of-4sqrt(x-1)+7 is (x^2+49}{16}-\frac{7x)/8+1