What is the inverse of f(x)=(3log_{6}(-7x-7))/4 ?

The inverse of f(x)=(3log_{6}(-7x-7))/4 is -(6^{(4x)/3}+7)/(7)

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inverse of f(x)=(3log_{6}(-7x-7))/4

inverse

f (x) = \frac{3 lo g _{6} ( - 7 x - 7 )}{4}

- \frac{6 ^{\frac{4 x}{3}} + 7}{7}

Solution steps

y = \frac{3 lo g _{6} ( - 7 x - 7 )}{4}

Replace

x

with

y

x = \frac{3 lo g _{6} ( - 7 y - 7 )}{4}

Solve for

y, x = \frac{3 lo g _{6} ( - 7 y - 7 )}{4}

- \frac{6 ^{\frac{4 x}{3}} + 7}{7}

(x + 1)^{2} + 2

\frac{2 x + 12}{3 x - 11}

f (x) = e^{2 x + 4}

f (x) = 4 ln (2 x - 5) + 7

\frac{1 - 2 x ^{3}}{x ^{3}}

What is the inverse of f(x)=(3log_{6}(-7x-7))/4 ?
The inverse of f(x)=(3log_{6}(-7x-7))/4 is -(6^{(4x)/3}+7)/(7)