What is the inverse of f(x)=(3x+1)/(2x-9) ?

The inverse of f(x)=(3x+1)/(2x-9) is (1+9x)/(2x-3)

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inverse of f(x)=(3x+1)/(2x-9)

inverse

f (x) = \frac{3 x + 1}{2 x - 9}

\frac{1 + 9 x}{2 x - 3}

Solution steps

y = \frac{3 x + 1}{2 x - 9}

Replace

x

with

y

x = \frac{3 y + 1}{2 y - 9}

Solve for

y, x = \frac{3 y + 1}{2 y - 9}

\frac{1 + 9 x}{2 x - 3}

f (x) = 3^{2 x - 1} - 2

\frac{3 s + 5}{s ^{2} + 4 s + 13}

\frac{2 s + 1}{s ^{2} - 2 s - 2}

ln (4 - 2 x)

f (x) = f (x) = 49 - x^{2}

What is the inverse of f(x)=(3x+1)/(2x-9) ?
The inverse of f(x)=(3x+1)/(2x-9) is (1+9x)/(2x-3)