What is the inverse of (x^2-2x-15)/(x^2-4x-21) ?

The inverse of (x^2-2x-15)/(x^2-4x-21) is (-5+7x)/(x-1)

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inverse of (x^2-2x-15)/(x^2-4x-21)

inverse

\frac{x ^{2} - 2 x - 15}{x ^{2} - 4 x - 21}

\frac{- 5 + 7 x}{x - 1}

Solution steps

y = \frac{x ^{2} - 2 x - 15}{x ^{2} - 4 x - 21}

Replace

x

with

y

x = \frac{y ^{2} - 2 y - 15}{y ^{2} - 4 y - 21}

Solve for

y, x = \frac{y ^{2} - 2 y - 15}{y ^{2} - 4 y - 21}

\frac{- 5 + 7 x}{x - 1}

g (x) = \frac{x}{x + 1}

f (x) = 30 x + 200

f (x) = 4 x^{(2)} - 8 x + 3

f (x) = lo g_{2} (x + 5) - 1

g (x) = \frac{x}{x + 2}

What is the inverse of (x^2-2x-15)/(x^2-4x-21) ?
The inverse of (x^2-2x-15)/(x^2-4x-21) is (-5+7x)/(x-1)