What is the inverse of f(x)=4x^{(2)}-8x+3 ?

The inverse of f(x)=4x^{(2)}-8x+3 is (2+sqrt(x+1))/2 ,(2-sqrt(x+1))/2

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inverse of f(x)=4x^{(2)}-8x+3

inverse

f (x) = 4 x^{(2)} - 8 x + 3

\frac{2 + x + 1}{2}, \frac{2 - x + 1}{2}

Solution steps

y = 4 x^{2} - 8 x + 3

Replace

x

with

y

x = 4 y^{2} - 8 y + 3

Solve for

y, x = 4 y^{2} - 8 y + 3

\frac{2 + x + 1}{2}, \frac{2 - x + 1}{2}

f (x) = lo g_{2} (x + 5) - 1

g (x) = \frac{x}{x + 2}

\frac{3}{2 + x}

f (x) = \frac{( x ^{2} - 1 )}{( x ^{2} + 1 )}

\frac{( x ^{2} + 7 x - 13 )}{x + 4}

What is the inverse of f(x)=4x^{(2)}-8x+3 ?
The inverse of f(x)=4x^{(2)}-8x+3 is (2+sqrt(x+1))/2 ,(2-sqrt(x+1))/2