What is the inverse of ((x^2+7x-13))/(x+4) ?

The inverse of ((x^2+7x-13))/(x+4) is (-7+x+sqrt(x^2+2x+101))/2 ,(-7+x-sqrt(x^2+2x+101))/2

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inverse of ((x^2+7x-13))/(x+4)

inverse

\frac{( x ^{2} + 7 x - 13 )}{x + 4}

\frac{- 7 + x + x ^{2} + 2 x + 101}{2}, \frac{- 7 + x - x ^{2} + 2 x + 101}{2}

Solution steps

y = \frac{x ^{2} + 7 x - 13}{x + 4}

Replace

x

with

y

x = \frac{y ^{2} + 7 y - 13}{y + 4}

Solve for

y, x = \frac{y ^{2} + 7 y - 13}{y + 4}

\frac{- 7 + x + x ^{2} + 2 x + 101}{2}, \frac{- 7 + x - x ^{2} + 2 x + 101}{2}

\frac{1}{t ^{2} + 1}

h (x) = \frac{2 x + 1}{3}

f (x) = 39.793 \cdot x + 1637.3

f (x) = (- 10 x + 1)^{2}

f (x) = \frac{2 x - 5}{4 x - 1} + 3

What is the inverse of ((x^2+7x-13))/(x+4) ?
The inverse of ((x^2+7x-13))/(x+4) is (-7+x+sqrt(x^2+2x+101))/2 ,(-7+x-sqrt(x^2+2x+101))/2