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Popular >

inverse of 1/(t^2+1)

Solution

inverse

\frac{1}{t ^{2} + 1}

Solution

\frac{1 - t}{t}, - \frac{1 - t}{t}

Solution steps

y = \frac{1}{t ^{2} + 1}

Replace

t

with

y

t = \frac{1}{y ^{2} + 1}

Solve for

y, t = \frac{1}{y ^{2} + 1}

\frac{1 - t}{t}, - \frac{1 - t}{t}

Graph

Popular Examples

inverse of h(x)=(2x+1)/3 inverse

h (x) = \frac{2 x + 1}{3}

inverse of f(x)=39.793*x+1637.3 inverse

f (x) = 39.793 \cdot x + 1637.3

inverse of f(x)=(-10x+1)^2 inverse

f (x) = (- 10 x + 1)^{2}

inverse of f(x)=(2x-5)/(4x-1)+3 inverse

f (x) = \frac{2 x - 5}{4 x - 1} + 3

inverse of (s-5)/((s+3)(s-2))inverse

\frac{s - 5}{( s + 3 ) ( s - 2 )}

Frequently Asked Questions (FAQ)

What is the inverse of 1/(t^2+1) ?
The inverse of 1/(t^2+1) is sqrt((1-t)/t),-sqrt((1-t)/t)