What is the inverse of log_{1/2}(16(1/2)^x)+2^3 ?

The inverse of log_{1/2}(16(1/2)^x)+2^3 is x-4

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inverse of log_{1/2}(16(1/2)^x)+2^3

inverse

lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{x}) + 2^{3}

x - 4

Solution steps

y = lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{x}) + 2^{3}

Replace

x

with

y

x = lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{y}) + 2^{3}

Solve for

y, x = lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{y}) + 2^{3}

x - 4

y = sin^{2} (x)

f (x) = (0.1)

f (x) = (x + 6)^{2} - 5

f (x) = (x + 6)^{2} - 4

f (x) = - \frac{31 x}{8} - 9

What is the inverse of log_{1/2}(16(1/2)^x)+2^3 ?
The inverse of log_{1/2}(16(1/2)^x)+2^3 is x-4