What is the inverse of f(x)=5x^2-3x-5 ?

The inverse of f(x)=5x^2-3x-5 is (3+sqrt(20x+109))/(10),(3-sqrt(20x+109))/(10)

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inverse of f(x)=5x^2-3x-5

inverse

f (x) = 5 x^{2} - 3 x - 5

\frac{3 + 20 x + 109}{10}, \frac{3 - 20 x + 109}{10}

Solution steps

y = 5 x^{2} - 3 x - 5

Replace

x

with

y

x = 5 y^{2} - 3 y - 5

Solve for

y, x = 5 y^{2} - 3 y - 5

\frac{3 + 20 x + 109}{10}, \frac{3 - 20 x + 109}{10}

f (x) = (\frac{( 7 x )}{( 8 x - 1 )})

f (x) = 2 y - 5

f (x) = y^{2} - 2 y

\frac{3 x}{4 x - 1}

What is the inverse of f(x)=5x^2-3x-5 ?
The inverse of f(x)=5x^2-3x-5 is (3+sqrt(20x+109))/(10),(3-sqrt(20x+109))/(10)